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-.12x^2+1x+6=0
We add all the numbers together, and all the variables
-0.12x^2+x+6=0
a = -0.12; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-0.12)·6
Δ = 3.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3.88}}{2*-0.12}=\frac{-1-\sqrt{3.88}}{-0.24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3.88}}{2*-0.12}=\frac{-1+\sqrt{3.88}}{-0.24} $
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